Question

Heating 1 g of silver metal in a current of dry chlorine

Answer 1

Answer:

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Explanation:

Silver chloride was prepared in two ways : <br> (i) 0.5 g of a silver wire was dissolved in concentrated nitric acid and the excess of hydrochloric acid was added to it. The precipitate of silver chloride was separated by filtration, washed, dried and then weighed. The weight of the residue was found to be 0.66 g <br> (ii) In another experiement, 1g of silver metal was heated in a current of chlorine till it was completely converted into its chloride which was found to weight 1.32 g <br> Show that the data is according to the Law of Constant composition.