heating coils, one of fine wire and other of thick wire made of same material and lengths are connected one by one to a source of electricity. Which coil produce heat at greater rate? Justify.
Answers
Answer:
Given,
2 heating coils of same length, l
Let resistance of thin wire be R
1
resistance of thick wire be R
2
We know,
for same material, resistivity ρ is same
Cross section area of thin wire = A
1
Cross section area of thick wire = A
2
A
2
>A
1
R=
A
ρl
⟹Rα
A
1
⟹R
1
>R
2
(∵A
2)
>A
1)
Rate of heat generation, P=
R
V
2
Both are connected to the same source V
Pα
R
1
⟹P
2
>P
1
(∵R
1
>R
2)
A thick wire coil will produce heat at a rate of heat generation, P=
R
V
2
Both are connected to the same source V
Pα
R
1
P
1
= Rate of heat generation by thin wire
P
2
= Rate of heat generation by thick wire
R
1
>R
2
⟹P
2
>P
1
The thick wire coil will generate heat at a greater rate.
Maybe I think this is helpful for you
Given,
2 heating coils of same length, l
Let resistance of thin wire be R1
resistance of thick wire be R2
We know,
for same material, resistivity ρ is same
Cross section area of thin wire = A1
Cross section area of thick wire = A2
A2>A1
R=ρl/A⟹Rα1/A
⟹R1>R2 (∵A2>A1)
Rate of heat generation, P=V/R
Both are connected to the same source V
PαR1
⟹P2>P1 (∵R1>R2)
A thick wire coil will produce heat at a rate of heat generation, P=V ² /R
Both are connected to the same source V
Pα1/R
P1 = Rate of heat generation by thin wire
P2 = Rate of heat generation by thick wire
R1>R2
⟹P2>P1
The thick wire coil will generate heat at a greater rate.
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