Question

Heating element connected to 230volt and current of 5ampere with amount of heat dispitated in 1hr?

Answer 1

Answer:

1.15 joule

0.238 calorie

Explanation:

the heating element connected to 230v draws a current of 5A

$I=\frac{v}{r}$

$r=\frac{v}{I}$

$r=\frac{230}{5}$= 46Ω

heat dissipated = $I^{2} rt$

                     =$5^{2}$×46×1

                    = 1150 wh

                    =1.15Kwh

                    =1.15 j

4.2j=1 calorie

1.15j=0.238

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Answer 2

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