Question

Heating together the solids NH4Cl and Ca(OH)2 can generate ammonia. Aqueous CaCl2 and liquid H2O are also formed. If a mixture of 33.0 g each of NH4Cl and Ca(OH)2 is heated, how many grams of NH3 will form? What is the limiting reagent? Which reactant remains in excess, and in what mass?

Answer 1

Answer:

7.58 g NH3 will be produced

Ca(OH)2 is limiting reagent and NH4Cl is excess reagent .

Explanation:

53.5g NH4Cl will produce 17 g NH3

1 g NH4Cl will produce 17/53.5 g NH3

33g NH4Cl will produce (17/53.5)×33g NH3

which is approximately equal to 10.48 g.

74g Ca(OH)2 will produce 17 g NH3

1g Ca(OH)2will produce 17/74g NH3

33g Ca(OH)2 will produce (17/74)×34g NH3

which is approximately equal to 7.58g.

Ans is the smaller value and the compound which gives less NH3 is limiting reagent.