Question

Hector received a pay raise this year. The raise was 6% of last year's salary. This year he will earn $15,900. What was his salary last year before the raise?

Answer 1

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$\huge \bf{Answer:}$

See a solution process below:


$\huge \bf{Explanation:}$


The formula for calculating a new salary is:

n=p+(p⋅r) Where:

n is the new salary: $15,900 for this problem.

p is the previous salary: what we are solving for in this problem.

r is the pay raise percentage: 6% for this problem. "Percent" or "%" means "out of 100" or "per 100", Therefore 6% can be written as 6100.

Substituting and solving for p gives:

$15900=p+(p⋅6100)

$15900=p+6p100

$15900=100100p+6100p

$15900=(100100+6100)p

$15900=106100p

100106×$15900=100106×106100p

$1590000106=100106×106100p

$15000=p

p=$15000

Hector's salary last year before the raise was: $15,000

hope it helps you..

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