Question

Heeeeeeeeeellllllppp!!!!!!!!!!
Ques - 1,2;3,3 &5 u get 100 pts

Answer 1

Hi friend,

(1) Given,

n=6.25×10^16
e=1.6×10^-19
t=2sec

I= Q/t [Q=ne]
I=ne /t

I=6.25×10^16× 1.6×10^-19/2

=10×10-³/2
I =5 m A.
~~~~~~~~~~~~~~~~~~~~~~~~~~~
2) I=ne/t

n= It/e

n= 1.6×10^-³×1/-1.6×10^-19

n= -10^16 electrons
(Note:- the negative sign represents the charge of the electrons. So it is omitted)
~~~~~~~~~~~~~~~~~~~~~~~~~~~
3) V=Ir

V= 200×10^-3 × 20
=4×10^-³+³

V=4V
~~~~~~~~~~~~~~~~~~~~~~~~~~~

4) V=IR
R=V/I

R= 6.0/1.2

R=5.0 ohm.
~~~~~~~~~~~~~~~~~~~~~~~~~~~

5) V=IR

R=V/I

R=12/2

R=6 ohm.

When the bulb is not flown there is minimum resistance acts in the bulb.So the resistance will be less in the bulb.
~~~~~~~~~~~~~~~~~~~~~~~~~~~

Hope this helped you a little!!!!!

Answer 2

1.c=e*no. of electrons / t
 C=  6.25 *10^16 *1.6 *10 ^ -19/ 2
6.25 * 1.6 * 10^ -3/2
5 * 10^ -3
0.0005 A or 5 mA


2. c=e*no. of electrons / t
1.6 *10^-3/ -1.6 * 10^-19 (1mA= 10^-3A)
10^-3/-10^-19
1/-10^16 = 10 ^16


3. V=IR
200 *20/1000
V=4V

4. V=IR
6.0 /1.2 =R
R=5ohm

5. V=IR
12/2 =R
R=6 ohm

sorry for delay
hope it will help u