Question

Heeeeyyyyyyyyyy frds plz help
Plz dont spam , i want answer with solution

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Answer 1

$\huge \underline\bold\red{Answer!!}$

Given----

Initial velocity (u) = 80km/h

$= \frac{80 \times 1000}{3600} = \frac{800}{36} {ms}^{ - 1}$

Now, final velocity (v) = 60km/h

$= \frac{60 \times 1000}{3600} = \frac{600}{36} {ms}^{ - 1}$

Time(T) = 5 second

To find out- Acceleration (a)?

Now ,

According to formula:-

$a = \frac{v - u}{t}$

$= \frac{ \frac{600}{36 } - \frac{800}{36} }{5}$

$= - \frac{ \frac{200}{36} }{5}$

$= - \frac{200}{36} \times \frac{1}{5}$

$= - \frac{10}{9}$

$= - 1.11ms {}^{ - 2}$

So , bus is decelerating at the rate of .

$= 1.11ms {}^{ - 2}$

Answer 2

Given data:

$Initial \: velocity \: (u)=80km/h$

$Final \: velocity (v)=60km/h$

$Acceleration \: (a)= ?$

Answer:

$The \: acceleration \: of \: the \: bus \: is \: \underline{- 1.1m {s}^{ - 2} }$

Step-by-step explanation:

$Initial \: velocity \: (u)=80km/h$

$= \frac{80 \times 1000}{3600}$

$\boxed{u= \frac{800}{36}m {s}^{ - 1} }$

$Final \: velocity (v)=60km/h$

$= \frac{60 \times 1000}{3600}$

$\boxed{v = \frac{600}{36}m {s}^{ - 1}}$

$Time \: \underline{(t)=5 \: seconds}$

$Acceleration \: \underline{(a)= \frac{v - u}{t}}$

$= \frac{ \frac{600}{36} - \frac{800}{36} }{5}$

$= \frac{ \frac{ - 200}{36} }{5}$

$= \frac{ - 10}{9}$

$\boxed{a = - 1.1m {s}^{ - 2} }$

$Therefore \: the \: acceleration \: of \: the \: bus \: is \: \underline{- 1.1m {s}^{ - 2} }$