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Solution:-
Let the required number of milliliters of alcohols be x ml.
Given 15 % of 400 ml should be added with 100 % of pure alcohol.
Hence 400(15 %) + x(100 %) = (400+x) (32 %)
⇒ 400 × 15/100 + x = (400 + x) × (32/100)
⇒ 60 + x = 128 + (8x/25)
⇒ x - 8x/25 = 128 - 60
⇒ 17x/25 = 68
⇒ x = (68 × 25)/17
⇒ x = 1700/17
x = 100 ml Answer.
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