Math, asked by HERCULESanswerKING, 10 months ago

Heena has 15% more sweets than Harish. By what percent is Harish's number of sweets less than
that of Heena's?​

Attachments:

Answers

Answered by ersanjay7192
14

Answer:

13.04%

Step-by-step explanation:

let x amount of sweet that harish has

so heena has 15% more than harish i.e. x + 0.15x = 1.15x

Harish's No. of sweet less than heena = 1.15x - x = 0.15x

less % = (0.15x / 1.15x) * 100

          = (15 / 115)* 100

          = 13.04%

Answered by rajaniprasad315
1

Answer:

13.04%

Step-by-step explanation:

Let the number of sweets Harish has be 100.

∴ number of sweets Heena has= 100 + 15% of 100

= 115

Hence, the percent by which Harish’s number of sweets less than that of Heena’s =  

Percent decrease = −

× 100

=  

115−100

115

× 100

=  

15

115

× 100

= 13.04%

Similar questions