heena has only rs 2 and rs 5 coins in her purse.if in all she has 80 coins in her purse amounting to rs 232,find the no of rs 5 coins
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let their be X coins of 2rs and Y coins of 5 rs.
X+Y=80
X=80-Y
If she has 80 coins in all then
2X+5Y=232
2(80-Y) +5Y =232
160-2Y+5Y=232
160+3Y=232
3Y=72
Y=24
or you can also have the possibility of
5x+2y=232
Using this you'll get y=56
you'll reject it because you
have total of 232rs it would exceed that (y=5rs & 5x56=280)
Please tell me was my answer correct
X+Y=80
X=80-Y
If she has 80 coins in all then
2X+5Y=232
2(80-Y) +5Y =232
160-2Y+5Y=232
160+3Y=232
3Y=72
Y=24
or you can also have the possibility of
5x+2y=232
Using this you'll get y=56
you'll reject it because you
have total of 232rs it would exceed that (y=5rs & 5x56=280)
Please tell me was my answer correct
hritikasawant:
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