Question

Height= 5, area= 50, find the base triangle.

Answer 1

$for \: the \: right \: anlged \: triangle \\ \\ area \: of \: triangle \: is \: given \: by \: \\ \\ \frac{1}{2} \times b \times h \: .. \: where \: b = \: base \: \\ \\ and \: h \: = \: hieght \: then \\ \\ 50 = \frac{1}{2} \times b \times 5 \\ \\ \: \frac{50 \times 2}{5} = b \\ \\ b = \frac{100}{5} \\ \\ b \: = 20$

Answer 2

$\pink{given:}$

area=50 unit sq.

height=5 unit
$\red{solution:}$


$area = \frac{1}{2} \times base \times height \\ \\ 50 = \frac{1}{2} \times base \times 5 \\ \\ \green{base = 20}$