Question

height and base of a right angled triangle are 24 cm and 18 cm . Find the length of its hypothenuse .​

Answer 1

Answer:

$\huge\boxed{\fcolorbox{pink}{red}{Verified Answer}}$

Let the right angled triangle be ∆ABC

Length of AB = 24cm

Length of BC = 18cm

ACCORDING TO PYTHAGORAS THEOREM , AB²+BC² = AC²

=> 24²+18² = AC²

=> AC² = 576 + 324

=> AC² = 900

=> AC = 30 {ROOT OF 900}

HENCE , THE LENGTH OF HYPOTENUSE IS 30cm.

HOPE IT HELPS UH...!!

Answer 2

Answer:

Here is your Answer :-

$given \: height \: of \: an \: right \: angled \: triangle \: = 24cm \\ and \: its \: base = 18cm \\ by \: using \: pythagorus \: theorem \: we \: get \\ hypothenuse^{2} \: = \: {height}^{2} + {base}^{2} \\ hypothenuse^{2} = (24 cm)^{2} + (18cm)^{2} \\ hypothenuse^{2} = 576 {cm}^{2} + 324 {cm}^{2} \\ hypothenuse = \sqrt{900 {cm}^{2} } \\ = > 30cm$

Hope it's helpful

Answered by :-

@MissInfinite