Math, asked by deencychheda, 4 months ago

Height and base of right
angle triangle are 24 and
18cm triangle . findd the length of its

hypoteurse​

Answers

Answered by bhagyashrineve05
0

Answer:

H = 30

Step-by-step explanation:

P=24

B=18

H=?

By pythagorus theorem

By pythagorus theorem (H)^2 =(P) ^2 + (B)^2

By pythagorus theorem (H)^2 =(P) ^2 + (B)^2(H)2 = (24)^2 + (18)^2

By pythagorus theorem (H)^2 =(P) ^2 + (B)^2(H)2 = (24)^2 + (18)^2(H)^2 = 576 + 324

By pythagorus theorem (H)^2 =(P) ^2 + (B)^2(H)2 = (24)^2 + (18)^2(H)^2 = 576 + 324(H)^2 = 900

By pythagorus theorem (H)^2 =(P) ^2 + (B)^2(H)2 = (24)^2 + (18)^2(H)^2 = 576 + 324(H)^2 = 900 (H)^2 = (30)^2

By pythagorus theorem (H)^2 =(P) ^2 + (B)^2(H)2 = (24)^2 + (18)^2(H)^2 = 576 + 324(H)^2 = 900 (H)^2 = (30)^2H = 30

Answered by sharanyalanka7
4

Answer:

Given,

A triangle is Right Angle Triangle.

Length of the Height of the Right Angle Triangle = 24cm

Length of the Base of the Right Angle Triangle = 18cm

To Find :-

Length of the Hypotenuse side of the Triangle .

Solution :-

Note :- Picture is in the attachment.

Let , the side of the Hypotenuse 'AC' = x

Height 'AB' = 24cm

Base 'BC' = 18cm

According to property of Right Angle Triangle :-

\sf (Hypotenuse)^{2} = (Adjacent Side)^{2} + (Height)^{2}

\sf{\implies\:Hypotenuse=\sqrt{(Adjacent\:side)^2+(Height)^2}}

Hypotenuse = \sf\sqrt{(18cm)^{2} + (24cm)^{2}}

AC = \sf\sqrt{324cm^{2} + 576cm^{2}}

AC = \sf\sqrt{900cm^{2}}

AC = \sf\sqrt{(30cm)^{2}}

AC = 30cm

\sf\therefore length of the Hypotenuse side = AC = 30cm.

Attachments:
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