Question

height at which the value of g becomes 1/4 to that on earth is​

Answer 1

Explanation:

gh = 1/4 g {given}

where, gh = acceleration due to gravity at height h

g = acceleration due to gravity

$\frac{gh}{g} = \frac{1}{4} \\ \frac{{r}^{2} }{(r + h) {}^{2} } = \frac{1}{4}$

Square Rooting both sides;

$\frac{r}{(r + h)} = \frac{1}{2} \\ 2r = r + h \\ r = h$

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Hope it helps...!

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