Question

Height of a plant whose genotype AaBb is 12 cm. It's minimum expression is 8 cm, then what is the maximum expression in this case​

Answer 1

Answer:

Contribution of each polygene = (Maximum height - Minimum height)/No. of polygene = (30 - 10)/6 = 3.3

Contribution of dominant polygene in plant having genotype AaBbCc= 3.3 x 3 = 9.9

Height of plant with genotype AaBbCc = Minimum height + Contribution of dominant polygene = 10 + 9.9 = 19.9 cm

Answer 2

AaBb $\\ = 12 cm$

Total dominant allele in AbBb is $2$.

aabb $\\ = 8 cm$

The partial contribution of each dominant allele can be given by:

 $\\ \frac{12-8}{2} = \frac{4}{2} = 2 cm$

The contribution of each dominant allele is $\\ 2 cm$ .

The genotype of Maximum expression can be given by $\\ = AABB$

The total dominant allele in AABB is $\\ 4$.

The height can be given by:

 $\\ mininmum\ expression + ( number \of\ dominant\ allele \times contribution \of \each\ dominant \allele)$

$8 cm + ( 4 \times 2)$

$\\ 8 cm + 8 cm = 16 cm.$

Hence, the maximum expression, in this case, is 16 cm.