Question

height of a right circular cylinder is 6m. 3times the sum of the areas of its 2circular faces is twice the area of its curved surface. find the radius of its base

Answer 1

height = 6m

A.T.Q,

3* sum of area of its bases = 2 * CSA

3 (2*pi*r*r)=2 ( 2 * pi * r * h)

pi and 2 will be cancelled out

3r= 2h

r=2×12/3

r=24/3

= 8 cm

Answer 2

$\sf \: Let \: radius \: of \: base \: be ′r′m. Then \\ 3(πr^2+πr^2)=2×2πrh \\ ⇒6πr^2=4πrh \\ ⇒r=\dfrac{4×6}{6}=4m$