Height of a right circular cylinder made of iron
open at two ends is 42 cm. If the thickness of
the cylinder is 1cm. and length of its external
diameter is 10cm. let us calculate the volume
Of iron in it.
Answers
Answered by
0
Answer:
sorry I am weak in mathematics
Answered by
5
Answer:
answer is 1188
Step-by-step explanation:
The length of external radius of cylinder = 10/2 cm = 5 cm
It is of 1 cm thickness.therefore, length of internal radius of the cylinder = (5-1) cm = 4 cm.
volume of iron
22/7(5^2 - 4^2)*42 cubic cm.
22/7*(5+4)(5-4)*42 cubic cm.
22/7*9*1*42 cubic cm.
22*9*6 cubic cm.
1188 cubic cm
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