Math, asked by anishjoshi, 5 months ago

Height of an equilateral Δ is √3cmFind the length of

side & perimeter of ΔABC

Height AD = √3cm ,ΔABC is …………….. ; AD =……… ,√3 =

……………,AB =……. = ……….= ……….,

perimeter of ΔABC = …….+…….+……. = ……..cm​

Answers

Answered by datmos661
0

Step-by-step explanation:

area of a equilateral Δ is √3/4*A2

area of triangle when height is given 1/2 *base *height

and let the sides be a

so

√3/4*A2=1/2 *base *heights

= a[/tex]

[tex] \frac{ \sqrt{3} }{4}  {a}^{2}  =  \frac{1}{2} base \times height \\ \frac{ \sqrt{3} }{4}  {a}^{2} =  \frac{1}{2} a \sqrt{3}  \\ \frac{ \sqrt{3} }{4}  {a}^{2} \times  \frac{2  }{ \sqrt{3} }  = a \\ \\ a = 2

perimeter =2+2+2=6cm

hope this will help

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