Question

Height of cylindrical part = 2.1 m
Diameter of cylindrical part = 4m
Slant height of conical part = 2.8 m

Find

Canvas used for making tent.
Cost of canvas of tent at the rate of ₹500
​

Answer 1

To Find :-

• Canvas used for making tent.
• Cost of canvas of tent at the rate of ₹500

Solution :-

Given

• Height of cylindrical part = 2.1 m
• Diameter of cylindrical part = 4m
• Slant height of conical part = 2.8 m

Formula used :-

• $\sf CSA \: of \: cylinder \: = \: 2\pi \: \: rh$
• $\sf CSA \: of \: cone \: = \pi \: rl$

$:\Rightarrow \sf \: Radius \: = \frac{Diameter}{2} \\ :\Rightarrow \: \frac{4}{2} = 2m \: \: \: \: \: \: \: \: \:$

• Required surface area = CSA of cone + CSA of cylinder

$:\Rightarrow \sf \: \pi \: rl \: + 2\pi \: rh$

$:\Rightarrow \sf \: \pi \: \: r(l + 2h)$

$:\Rightarrow \sf \: \frac{22}{7} \times 2 \times (2.8 + 2 \times 2.1)$

$:\Rightarrow \sf \: \frac{44}{7} (2.8 + 4.2)$

$:\Rightarrow \sf \frac{44}{7}\times7 \: :\Rightarrow 44 \: {m}^{2}$

Cost of canvas of tent at the rate of ₹500 per metre square is =

$\sf \: 44 \times 500 = ₹22000$

Hence,

• Required answer ${\boxed{\sf{\red{ ₹22000}}}}$

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Answer 2

Your answer refer to the attached photo