Question

height of height of a cylindrical barrel is 50 cm and radius of its base is 20 CM Anurag started to fill the barrel with water when it was empty by a cylindrical box the diameter and height of The Monk was 10 cm and 50 and 15 cm is equal to how many minimum number of marks will be required for the barrel to overflow

Answer 1

Answer:

Step-by-step explanation:

Volume of barrel is =V=$\pi 20^{2}*50= 62800 cm^{3}$

Diameter of monk=10cm;

so radius is 5cm;

Height of monk=15 cm;

Volume of monk is=$\pi 5^{2}*15$=1177.5 cm$^{3\\}$;

Number of monk required for the b$\frac{62800}{1177.5} =53.3$arrel to overflow >

Minimum number of monk=54 approx

Answer 2

Answer:

Step-by-step explanation:

Volume of barrel is =V=\pi 20^{2}*50= 62800 cm^{3}π20

2

∗50=62800cm

3

Diameter of monk=10cm;

so radius is 5cm;

Height of monk=15 cm;

Volume of monk is=\pi 5^{2}*15π5

2

∗15 =1177.5 cm;

Number of monk required for the b\begin{lgathered}\frac{62800}{1177.5} =53.3\\\end{lgathered}

1177.5

62800

=53.3

arrel to overflow >

Minimum number of monk=54 approx