Height of the isosceles triangle is 6 cm.Its perimeter is 36 cm.Find its area
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Since perimeter = 36 and base is 16. Each side is 10 (10+10+16 = 36 perimeter)
In an isoceles triangle, the perpendicular from the 3rd point of the triangle on the base divides the base.
So half of base and height and one side becomes a right triangle
Now using pythagoras theorem
h^2 = side^2 - (base/2)^2
= 100 - 64 = 36
h = 6
Area of traiangle = 1/2 * b * h
= 1/2 * 16 * 6
= 48 sq cm.
Hope this helps
In an isoceles triangle, the perpendicular from the 3rd point of the triangle on the base divides the base.
So half of base and height and one side becomes a right triangle
Now using pythagoras theorem
h^2 = side^2 - (base/2)^2
= 100 - 64 = 36
h = 6
Area of traiangle = 1/2 * b * h
= 1/2 * 16 * 6
= 48 sq cm.
Hope this helps
MVN:
how base will be 16 ???????
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