Question

height of the tower is 30 M calculate the length of its Shadow made on the level ground when the sun and sons altitude is 60 degree

Answer 1

Tan 60=root 3
Root 3=30/shadow
Shadow=30/root 3
=30/1.732
=17.32
Approximately =17m

Answer 2

The length of shadow is 10√3 m.

Step-by-step explanation:

It is given that height of the tower is 30 m and sun and sons altitude is 60 degree.

Let x be the length of shadow.

In a right angle triangle

$\tan \theta=\dfrac{opposite}{adjacent}$

$\tan (60)=\dfrac{30}{x}$

$\sqrt{3}=\dfrac{30}{x}$

$x=\dfrac{30}{\sqrt{3}}$

On rationalization we get

$x=\dfrac{30}{\sqrt{3}}\times \dfrac{\sqrt{3}}{\sqrt{3}}$

$x=\dfrac{30\sqrt{3}}{3}$

$x=10\sqrt{3}$

Therefore, the length of shadow is 10√3 m.

#Learn more

At a particular time suns altitude is 30 degrees. The length of shadow of vertical tower is 45 m. Calculate height of tower.

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