Question

height of the tree is 15 m and it is broken at 5m from the bottom and form an angle of elevation find the angle​

Answer 1

Answer:

30°

Step-by-step explanation:

let the top of tree be A and bottom be B so AB = 15m , So let it be broken from C such that BC is 5m , so AC = 10m ( just visualise or draw on copy accordingly to understand better)

So , right triangle ABC is formed 90° at B

We need to find first BC and then angle A

So BC²+ BA² = AC²

BA² = AC²- BC²

BA² = 10²- 5²

BA² = 100 -25

BA² = 75

BA = √75

BA = 5√3

tan A = BC/BA

= 5/5√3

= 1/√3

But tan 30° = 1/√3

so , Angle A = 30°

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