heights of Anshul, Ankitha and Dhruv are 1.04 metre, 1.30 and 91 cm respectively. Divide 100 sweets among them in the ratio of their heights.
Answers
Answer:
Anshul: 32 sweets
Ankitha: 40 sweets
Dhruv: 28 sweets
Step-by-step explanation:
Height of Anshul = 1.04m
Height of Ankitha = 1.30m
Height of Dhruv = 0.91m
Total height of three children = 1.04 + 1.30 + 0.91 = 3.25m
Share of Anshul in total height in % = 100*(1.04/3.25) = 100*0.32 = 32
Share of Ankitha in total height in % = 100*(1.30/3.25) = 100*0.40 = 40
Share of Dhruv in total height in % = 100*(0.91/3.25) = 100*0.28 = 28
As the shares are expressed in percentages (out of 100), we can divide 100 sweets as:
Anshul: 32 sweets
Ankitha: 40 sweets
Dhruv: 28 sweets
Step-by-step explanation:
height of
Anshul : 1.04 m
Ankita: 1.30m
Dhruv : 91 cm
therefore the height of Anshul and Ankita in cm
104cm, 130cm
ratio of heights :-
104 : 130 : 91 = 8: 10: 7
to divide 100 sweets among them in the ratio of 8 : 10 : 7 will be,
sum of 8,10,7 = 25
therefore sweets to Anshul = 8/25 ×100 sweets = 32 sweets
sweets to Ankita = 10/25×100 sweets = 40 sweets
sweets to Dhruv = 28 sweets
hence, 32 sweets to Anshul, 40 sweets to Ankita
and 28 sweets to Dhruv