heights of similar triangles are 2cm and 3 cm respectively, find the ratio of their areas. (a.)2:3 (b) 3:2(c)4:9(d)9:4
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if height of two similiar triangles are 2 and 3cm
let first triangle be a ABC and second be a PQR
THEN THE RATIO OF AREA OF TRIANGLES IS ALSO EQUAL THE SQUARE OF RATIO OF THEIR MEDIANS{HEIGHT}
ar{ABC}/ar{PQR}=2SQUARE/3SQUARE
4/9
SO OPTION {c}=4:9 is right one
let first triangle be a ABC and second be a PQR
THEN THE RATIO OF AREA OF TRIANGLES IS ALSO EQUAL THE SQUARE OF RATIO OF THEIR MEDIANS{HEIGHT}
ar{ABC}/ar{PQR}=2SQUARE/3SQUARE
4/9
SO OPTION {c}=4:9 is right one
Gopesh11:
no
i have imagine 2:3 answer is right.
how
because the area of triangle1÷2×base×height
am i right sr
i think my answer is right confirm with other
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