Question

helicopter, this one also
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Answer 1

Answer:

the value of the following is 0

Step-by-step explanation:

the both values are same

+x- = 0 so in the following

question there is +,- there is

pythogorus mean bracket

bracket means multiplication

so +x- do subtraction for both the values

answer is0.

Answer 2

$\huge \fbox \orange{Answer:}$

$\sf \colorbox{pink} {Here, } \sf \colorbox{lightgreen} {Using the Property}$

$➧(a + b {)}^{2} = (a {)}^{2} + (b {)}^{2} + 2ab$

$➧(a - b {)}^{2} = (a {)}^{2} + (b {)}^{2} - 2ab$

$\fbox{So,}$

$⇒[( \frac{3}{2} {)}^{2} + ( \sqrt{6} {)}^{2} + 2 \times \frac{3}{2} \times \sqrt{6} ]$

$⇒[( \frac{3}{2} {)}^{2} + ( \sqrt{6} {)}^{2} - 2 \times \frac{3}{2} \times \sqrt{6} ]$

$= ( \frac{9}{4} + 6 + 3 \sqrt{6} )( \frac{9}{4} + 6 - 3 \sqrt{6} )$

$= \frac{9}{4} ( \frac{9}{4} + 6 - 3 \sqrt{6} ) + 6( \frac{9}{4} + 6 - 3 \sqrt{6} ) + 3 \sqrt{6} ( \frac{9}{4} + 6 - 3 \sqrt{6} )$

$= \frac{81}{16} + \frac{54}{4} - \frac{27 \sqrt{6} }{4} + \frac{54}{4} + 36 - 18 \sqrt{6} + \frac{27 \sqrt{6} }{4} + 18 \sqrt{6} - 9 \times 6$

$= \frac{81}{16} + \frac{54}{4} + \frac{54}{4} + 36 - 54$

$= \frac{81}{16} + \frac{54}{4} + \frac{54}{4} - 18$

$\textbf{Now Taking L.C.M. of 16, 4= 16}$

$= \frac{81}{16} + \frac{54 \times 4}{4 \times 4} + \frac{54 \times 4}{4 \times 4} - \frac{18 \times 16}{1 \times 16}$

$= \frac{81 + 216 + 216 - 288}{16}$

$= \frac{225}{16}$

$\textbf{:Hence the Value is } = \frac{225}{16}$

$\\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$