Helium at 27°C has a volume of 8 litres. It is suddenly compressed to a volume of 1
litre. The temperature of the gas will be [y = 5/3]
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Helium at 27∘C has a volume of 8 litres. It is suddenly compressed to a volume of 1 litre. The temperature of the gas will be [γ=5/3] JEE main paper will be in multilingual and preference will be given to states with maximum number of applications.
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37.5 will be the final temperature
Explanation:
Apply the eqn (V1/V2)=(T2/T1)^{1/(y-1)}
Here (V1/V2)=2, T1=273+27=300°K,y=1.5
=>(T2/T1)=2^(y-1)=2^(1.5–1)=√2
So T2=300√2=424.2°K or 424.2–273=151.2°C.
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