Chemistry, asked by milap31, 11 months ago

Helium atom can be excited 1s1 2p1 by Lambda = 58.4 NM is the lowest excited state for the Helium lies in 4857cm -1 below the above then calculate the energy of the lower excitation state​

Answers

Answered by drnmishra1
10

Answer:

3.3 X 10^-18 J

Explanation:

Here it is.

Attachments:
Similar questions