Helium atom can be excited 1s1 2p1 by Lambda = 58.4 NM is the lowest excited state for the Helium lies in 4857cm -1 below the above then calculate the energy of the lower excitation state
Answers
Answered by
10
Answer:
3.3 X 10^-18 J
Explanation:
Here it is.
Attachments:
Similar questions