Question

Helium balloon deflates at rate of 1 liter per day how fast co2 leak from same balloon

Answer 1

Answer:

0.3 litre/day

Explanation:

Using graham's law,

$\frac{r_{1} }{r_{2}}$ = √M₂/√M₁

Where r₁ and r₂ are the rates of effusion and M₁ and M₂ are the molecular weights.

Molecular weight of He (M₁)= 4

Molecular weight of CO₂(M₂) = 44

Rate of effusion of helium(r₁) = 1 litre /day

Putting these values in formula,

1/r₁ = √44/√4

Squaring both sides,

1/(r₁)²= 44/4

1/11 = (r₁)²

r₁ = 0.3 litre/day

Hope it helps..!! ^_^