Helium gas consist of a single atom.What mass of helium atons 6.022x10e23 atoms
Answers
Answered by
1
It is equal to 1 mole of helium gas, i.e. 4g
Answered by
2
as we know
atomic weight for He = 4
n(mole) = wt/Atwt = N/NA
wt = weight
Atwt= atomic weight
N = no. of atoms
NA = avogadro number = 6.022x10^23
so wt /4 = (6.022x10^23)/(6.022x10^23)
then wt = 4 gm of helium consist 6.022x10^23 atoms
atomic weight for He = 4
n(mole) = wt/Atwt = N/NA
wt = weight
Atwt= atomic weight
N = no. of atoms
NA = avogadro number = 6.022x10^23
so wt /4 = (6.022x10^23)/(6.022x10^23)
then wt = 4 gm of helium consist 6.022x10^23 atoms
ishaandhar07:
Thank you so much
welcomn nd mention not ...it's mahh plasor
Similar questions