Question

Helium gas is filled in two identical
bottles A and B. The mass of the
gas in the two bottles is 10 gm and
40 gm respectively. If the speed of
- sound is the same in both bottles,
what conclusions will you draw?
plz answer​

Answer 1

$\bf{\boxed{\boxed{Answer:-}}}$

◻ Here, the conclusion is Temperature in bottle A is less than in Bottle B.

$\bf{\boxed{\boxed{Solution:-}}}$

Here, Given that :-

• Mass of helium in bottle A = 10gm
• Mass of helium in bottle B= 40gm

Velocity of bottle A =Velocity of Bottle B.

=> Va = Vb = v

We know that,

V is directly proportional to

$\sqrt{ \frac{t}{m} }$

T = temperature

So,

$\frac{ta}{ma} = \frac{tb}{mb}$

$\frac{ta}{tb} = \frac{ma}{mb}$

$\frac{ta}{tb} = \frac{10}{40} = \frac{1}{4}$

So, temperature in bottle A < temperature in bottle B.

Answer 2

Answer:

Here, the conclusion is Temperature in bottle A is less than in Bottle B.

\bf{\boxed{\boxed{Solution:-}}}Solution:−

Here, Given that :-

Mass of helium in bottle A = 10gm

Mass of helium in bottle B= 40gm

Velocity of bottle A =Velocity of Bottle B.

=> Va = Vb = v

We know that,

V is directly proportional to

\sqrt{ \frac{t}{m} }mt

T = temperature

So,

\frac{ta}{ma} = \frac{tb}{mb}mata=mbtb

\frac{ta}{tb} = \frac{ma}{mb}tbta=mbma

\frac{ta}{tb} = \frac{10}{40} = \frac{1}{4}tbta=4010=41

So, temperature in bottle A < temperature in bottle B.