Question

helium gas is filled in two identical bottles A and B. the mass of two bottles is 10 gm and 40 gm respectively. if the speed of sound is same in two bottles, what conslusion will you draw?

Answer 1

Does you got it.friend

Answer 2

The conclusion drawn is that temperature in bottle B is four times as that of A.

Helium gas is filled in two identical bottles, A and B.

Mass of bottle A = 10gm

Mass of bottle B = 40gm

Goven that the velocity of sound is the same in both bottles.

So, Va = Vb = V       [ Va and Vb are speed of sound in bottle A and B respectively]

As v ∝ √(T/M)   , where T is temperature and M is mass.

As, Va = Vb. So,

√(Ta/Ma)  =  √(Tb/Mb)     [Ta, Ma are temperature and masses of bottle A]

Squaring both sides,

(Ta/Ma)  =  (Tb/Mb)

Ma = 10gm and Mb = 40gm,

So, Ta/Tb = Ma/Mb = 10/40 = 1/4

Tb = 4Ta.

Temperature in bottle B is four times as that of A.