helium. gas. is. filled. in. two. identical. bottles A and B the. mass. of the gas in the two. bottles. is 10gm. and. 40gm respectively. if the. speed. of. sound. is. the. same in. both. bottles. what. conclusions. will. you. draw.
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hlo mate
here is ur answer
Mass of helium in bottle A is 10g = M1
Mass of helium in bottle B is 40g=M2
Speed of sound in bottle A is equal to speed of sound in bottle B
V1 =V2
Therefore , root T1 / root M1 - root T2 / root M2
Therefore, T1 / M1 - T2 / M2
Therefore , T1 / 10 - T2 / 40 ( 4 T1 =T2 )
Temperature of bottle B is 4 times that of Bottle A.
here is ur answer
Mass of helium in bottle A is 10g = M1
Mass of helium in bottle B is 40g=M2
Speed of sound in bottle A is equal to speed of sound in bottle B
V1 =V2
Therefore , root T1 / root M1 - root T2 / root M2
Therefore, T1 / M1 - T2 / M2
Therefore , T1 / 10 - T2 / 40 ( 4 T1 =T2 )
Temperature of bottle B is 4 times that of Bottle A.
komalchoudhary53900:
pls mark as brainliest
4T1=T2
How u got it .Can u tell please
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