Question

Helium gas is filled into two glass bulbs of volumes V0 and 4V0 such that the pressure in the two bulbs is P0 and 3P0 respectively. Initially the thin tube connecting the bulbs is blocked by a tap. When the tap is opened and the gas flow stops, find the pressure in the smaller bulb Assume temperature is same and constant .

PLS ANSWER FAST

Answer 1

Answer:

At first, at 273K

the mole in each bulb =

2

n

total

=

2

1

.

RT

P.2V

=

273×R

76V

On heating second bulb, some mole of gas are transferred to another bulb until the pressure of both bulb become same.

∴n

1

=

273R

P×V

and n

2

=

R×335

PV

n

total

=n

1

+n

2

⇒2×

273R

76V

=

273R

P×V

+

335×R

PV

⇒P=83.75 unit of Ag.