Math, asked by bhavani27, 1 year ago

hellllllllllloooooooo

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Answered by NidhraNair
16
hello..



please refer the above attachment....

thank you ☺
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Anonymous: hello
Answered by Anonymous
11
Given Equation :

4-2(K+1)+K²+K-8<0

Solution of the equation :

4-2(K+1)+K²+K-8<0

2(K+1)+K²+K-8<0

K²+2K+2+K-8<0

K²-K-6<0

(K-3) (K-2)<0

-2 < K < 0

So from above we can say that ,

K€(-2,3)
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