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Answered by
3
given radius of the bigger circle 9 cm
its area become πr²
3.14×81=254.34 cm²
and another circle that cut has radius 4cm
3.41×16
=50.24 cm²
remaining area be
254.34 - 50.24 cm²
= 204.12 cm²
hope it help you dear
its area become πr²
3.14×81=254.34 cm²
and another circle that cut has radius 4cm
3.41×16
=50.24 cm²
remaining area be
254.34 - 50.24 cm²
= 204.12 cm²
hope it help you dear
Answered by
3
Given radius of metal sheet = 9 cm.
Given that circle of radius 4 cm is removed.
Now,
Area of circular sheet = πr^2
= > (3.14) * (9)^2
= > 254.34cm^2.
(2) Area of removed part = πr^2
= > (3.14)(4)^2
= > 50.24cm^2.
Hence,
The area of remaining sheet = 254.34 - 50.24
= > 204.1cm^2.
Therefore, the area of remaining sheet = 204.1cm^2.
Hope it helps!
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