Question

helllo guys...... plz solve this equation I will definitely mark as brainliest ​

Answer 1

Answer:

$(3 - 4x + 5) \div (x + 1) = (4 - x) \div (x - 1) \\ (3 - 4x - 5) \times (x - 1) =( x + 1) \times (4 - x) \\ 3x - {4}^{2} - 5x - 3 + 4x + 5 = 4x + 4 - {x}^{2} - x \\ 2x + 2 - {4}^{2} = 3x + 4 - {x }^{2} \\ 2x - 3x - {x}^{2} = 2 - 16 + 4 \\ - x - {x}^{2} = 6 + 16 \\ - x - x = 6 + 4 \\ - 2x = 10 \\ x = 10 \div ( - 2) \\ x = ( - 5)$

-5 is the answer.

Answer 2

Answer:

3-4x+5/x-1=4-x/x-1

first we will cross multiply 4x+5 with x-1

nd we will cross multiply x+1 with 4-x

so,

4x+5(x-1)= 4x+ 5x-5

= 9x-5.......i

x+1(4-x)= x+4-x.......ii

now we will equate both the equations i nd ii

9x-5=x+4-x

9x-5-x-4+x =0

9x-x+x-5-4 =0

9x -1 =0

Therefore,

9x =1

x = 1/9...