Question

Hello !

1.)
The mid value of class interval is 52 If the class size is 10 .Then upper and lower limit of the class.Find it
2.)
In attachment


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Answer 1

Answer:

Let the upper limit and lower limit of the class be x , y

then (x+y)/2 = 42

or x+y = 84

x-y = 10

solving equations x = 47 , y = 37

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Answer 2

$\huge\bf{Answer:-}$

Refer the attachment (1) , (2) and (3).