Math, asked by ty009, 1 year ago

hello

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Answers

Answered by brunoconti

Answer:

Step-by-step explanation:

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ty009: Hi try this maths TB. ch2 pg2.8 Q39.

https://brainly.in/question/9117958?utm_source=android&utm_medium=share&utm_campaign=question

Answered by siddhartharao77

Answer:

Option(D)

Step-by-step explanation:

$Given:log_{a}b + log_{a}c = 0$

$=>log_{a}b=-log_{a}c$

$=>log_{a}b = log_{a}\frac{1}{c}$

$=>b = \frac{1}{c}$

∴ b and c are reciprocals.

Hope it helps!

ty009: why we should take log_a 1/c ??? can't understand why it appeared....

siddhartharao77: a^-1 => (1/a)

siddhartharao77: here, log is in negative term. So, in order to make it positive, make reciprocal!

ty009: Ok.....reciprocal, got it! Thank you bro. Marked you and brainliest.

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