Math, asked by Anonymous, 10 months ago

hello

A number of two digits exceeds four times the sum of its digits by 3.If 36 is added to the number, the digits are reversed. Find the number.

#Urgently needed

Tnxaa​


wardahd1234: Mhmmmm
wardahd1234: what?

Answers

Answered by Anonymous
12

SOLUTION____✒️

Let the unit Digit of the number be x and ten's digit be y.

the number= 10y+x

=10y+x= 4(x+y)+3

=10y+x -4x- 4y= 3

= -3x+6y= 3

= -x+2y= 1___________(1)

the number by reversing its Digit= 10x+y

= 10y+x= 10x+y+36

= -9x+9y= 36

= -x+y=4__________(2)

Subtracting equation (2) from (1):

x=0, y= -3

the number is -30 ans.

#️⃣MARK BRAINLIEST✓✓


Anonymous: answer is 59
Anonymous: Answer wrong hoga
Answered by wardahd1234
42

Let x = tens digit

y = unit digit

10x+y = the number

10y+x = the reversed number

The number of two digit exceeds 4 times the sum of the digits by 3

10x+y = 4(x+y)+3

If 36 is added to the number the digits are reversed

10y+x = 10x+y+36

9y = 9x+36

y = x+4

Substitute y with x+4

10x+x+4 = 4(x+x+4)+3

11x+4 = 4(2x+4)+3

11x+4 = 8x+19

3x = 15

x = 5

y = 9

The number is 59.

Let's

Check

59+36 = 95

95 = 95

59 = 4(9+5)+3

59 = 4(14)+3

59 = 56+3

59 = 59

Thanks!


Anonymous: tq sir
wardahd1234: :')
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