Question

Hello all ¡! ☺
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⚫⚪Class 11⚪⚫
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⚫⭕Can I get some notes on
➖banking of roads➖⭕⚫
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❌✖No spamming✖❌
✖No Short answers✖
✖No googled answers✖
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Answer 1

 

Banking of road:

The process of raising outer edge of a road over its inner edge through certain angle is known as banking of road.

Necessity of banking of the road:

i. When a vehicle moves along horizontal curved road, necessary centripetal force is supplied by the force of friction between the wheels of vehicle and surface of road.

ii. Frictional force is not enough and unreliable every time as it changes when road becomes oily or wet in rainy season.

iii. To increase the centripetal force the road should be made rough. But it will cause wear and tear of the tyres of the wheel.

iv. Thus, due to lack of centripetal force vehicle tends to skid.

v. When the road is banked, the horizontal component of the normal reaction provides the necessary centripetal force required for circular motion of vehicle.

vi. Thus, to provide the necessary centripetal force at the curved road, banking of road is necessary.

CONGRATS!

Answer 2

Hey buddy!!...

The phenomenon of raising outer edge of the curved road above the inner edge is to provide necessary centripetal force to the vehicles to take a safer turn and the curved road is called Banking of Roads.

Introduction

When a vehicle goes round a curved road, it requires some centripetal force. While rounding the curve, the wheels of the vehicle have a tendency to leave the curved path and regain the straight line path. Force of friction between wheels and the roads opposes this tendency of the wheels. This force of friction therefore, acts towards the centre of circular track and provides the necessary centripetal force.

a vehicle of weight ‘mg’ (acts vertically downwards) is moving on a level curved road. R1 and R2 are the forces of normal reaction of the road on the wheels. These are vertically upward since road is leveled. Hence,

R1 + R2 = mg

Let F1 & F2 are forces of frictions between tyre and road directed towards centre of curved road.

∴ F1 = μ R1

And

F2 =  μ R2

where μ is coefficient of friction between tyres and road.

If ‘v’ is the velocity of the vehicle while rounding the curve, the centripetal force required is mv²/r. As this force is provided by the force of friction therefore



Hence the maximum velocity with which a vehicle can go round a level curve; without skidding is


Hope this helps u!!