Math, asked by Sladepplayz, 5 hours ago

hello all pls answer these 2 questions​

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Answered by sandy1816
0

  \frac{5 - 2 \sqrt{3} }{5 + 2 \sqrt{3} }  = a + b \sqrt{3}  \\  \frac{5 - 2 \sqrt{3} }{5 + 2 \sqrt{3} }  \times  \frac{5 - 2 \sqrt{3} }{5 - 2 \sqrt{3} }  = a + b \sqrt{3}  \\  \frac{25 + 12   - 20 \sqrt{3} }{25 - 12}  = a + b \sqrt{3}  \\  \frac{37 - 20 \sqrt{3} }{13}  = a + b \sqrt{3}  \\  \frac{37}{13}  -  \frac{20}{13}  \sqrt{3}  = a + b \sqrt{3}  \\  \\ a =  \frac{37}{13}  \:  \:  \:  \:  \: \:  \:  \:  \:   \:  b =  -  \frac{20}{13}  \\  \\  \\ \frac{2 + 3 \sqrt{3} }{4 - 5 \sqrt{3} }  = a + b \sqrt{3}  \\  \\  \frac{2  + 3 \sqrt{3} }{4 - 5 \sqrt{3} }  \times  \frac{4 + 5 \sqrt{3} }{4 + 5 \sqrt{3} }  = a + b \sqrt{3}  \\  \\  \frac{8 + 10 \sqrt{3} + 12 \sqrt{3}   + 45}{ {4}^{2} - ( {5 \sqrt{3} })^{2}  }  = a + b \sqrt{3}  \\  \\  \frac{53 + 22 \sqrt{3} }{ - 59}  = a + b \sqrt{3}  \\  \\  -  \frac{53}{59}  -  \frac{22}{59}  \sqrt{3}  = a + b \sqrt{3}  \\  \\ comparing \: both \: sides \\ a =  -  \frac{53}{59}  \\  \\ b =  -  \frac{22}{59}

Answered by AnjanaUmmareddy
1

Answer:

"This is the answer but question and answer is different"

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