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Why does ➖Pbl4➖ does not exist ??
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NidhraNair:
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Answered by
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Hey mate, here is your answer -:)
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The Iodide reduces the lead to Pb(II) and the Pb oxidizes the Iodide to Iodine (I2). Since iodide is not a strong enough reducing agent to reduce Pb(II) to Pb, the ionic compound PbI2 is formed. Pb4+ , being a strong acid (strong oxidant) will take up electrons from soft base (have fairly good reducing power) I- to oxidise it to I2 and it self will reduce to Pb2+ to form PbI2.
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The Iodide reduces the lead to Pb(II) and the Pb oxidizes the Iodide to Iodine (I2). Since iodide is not a strong enough reducing agent to reduce Pb(II) to Pb, the ionic compound PbI2 is formed. Pb4+ , being a strong acid (strong oxidant) will take up electrons from soft base (have fairly good reducing power) I- to oxidise it to I2 and it self will reduce to Pb2+ to form PbI2.
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Answered by
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Answer:
PbI4 does not exist because the iodine reduces the lead to Pb(II) and the Pb oxidizes the iodine to iodine(I2). Since the iodine is not a strong reducuing agent to reduce Pb(II) to Pb, the compound Pbl2 is formed.
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