hello ans 19 and 20 questions
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cchinni64:
thanq u a lot
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heya #chhini64....here is ur answer...
19..(tan60°-tan30°)/(1+tan60°tan30°).....(1)
we already know that.....
tan(a-b)= (tana - tanb)/(1+tanatanb)
so.....eq(1) is gets converted into....
tan(60-30)
tan30°.......
hence tan30° is the correct one...
20.cosx=cos60°cos30°+sin60°sin30°...(1)
so solve rhs...first....
we know that....
cos(a-b)=cosacosb +sinasinb........
from eq (1)..rhs side..convert it into....cos(a-b)...
so...it will be...cos(60-30)....
which is cos(30°)........
now compare both side...
cosx=cos30°....
the value of x = 30°....
hence proved
19..(tan60°-tan30°)/(1+tan60°tan30°).....(1)
we already know that.....
tan(a-b)= (tana - tanb)/(1+tanatanb)
so.....eq(1) is gets converted into....
tan(60-30)
tan30°.......
hence tan30° is the correct one...
20.cosx=cos60°cos30°+sin60°sin30°...(1)
so solve rhs...first....
we know that....
cos(a-b)=cosacosb +sinasinb........
from eq (1)..rhs side..convert it into....cos(a-b)...
so...it will be...cos(60-30)....
which is cos(30°)........
now compare both side...
cosx=cos30°....
the value of x = 30°....
hence proved
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