hello anyone can solve this problem please if f'(x) =k(cosx-sinx),f'(0)= 3,f(π/3)=15,then find k?
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793₹ shelve !&::?28 @383): dleiene
Answered by
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f(pie/3)=15
it means theta=60
(cos60-sin60)k=15
(1/2-root3/2)k=15
(1-root3)k/2=15
(1-root3)k=30
then
f'(0)=k(cos0-sin0)
=k(1-0)=3
so
k=3
it means theta=60
(cos60-sin60)k=15
(1/2-root3/2)k=15
(1-root3)k/2=15
(1-root3)k=30
then
f'(0)=k(cos0-sin0)
=k(1-0)=3
so
k=3
AryadhaSharma2002:
ok
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