Question

Hello Baccho
answer this
The length and breadth of a rectangular tank are 3.0 m and 2.0 m . It contains Water Up to The height of 1.5m Calculate the Total Thrust and Pressure at the bottom of the tank Due to Water . Density of Water =1000 kg/m^3 and g = 10 m/s^2

Answer 1

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L=3m and B=2m

so,

area =LxB=6m2

now,

volume= 3x2x1.5=9m3

Fb=VxDxg

=90000N

pressure = Force/area

=15000p.a

Answer 2

Hello Mam

Answer

Volume of water = Length * Breadth * height

                            = (3.0 m ) * (2.0 m)  * (1.5 m)

                            = (6.0*1.5) m

                            = $9.0^{3} m$

Now

Mass of water , M =  Volume * Density

                              = $(9.0 m^{3} )$ * $(1000 kg/m^{3} )$

                              = $9000 kg$

Again

Weight of water , W = Mg =  $9000* 10^4$

Total thurst of water on the bottom of tank

F = Weight of water

  = $90*10^4$

 

Area of bottom = Length * Breadth

                          = 3.0 * 2.0

                          = $6.0^2m$

NOW

Pressure of water at the bottom

P= Force/area of bottom

= $9*10^4/6.0$

= $1.5*10^4 N/m ^2$

                                                                                                                                                       

Hope it helps you