Question

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QUESTION FOR YOU

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Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?

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Answer 1

Answer:

1. x³+y³+z³ = 8

=1³+(-1)³+2³

=1-1+8

=0+8

=8.

Step-by-step explanation:

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Answer 2

Answer:

$1.x {}^{3} + y {}^{3} + z {}^{3} = 8$

$= 1 {}^{3} + \binom{ - 1}{} {}^{3} + 2 {}^{3}$

$= 1 - 1 + 8$

$= 0 + 8$

$= 8$.