Physics, asked by Anonymous, 1 month ago

Hello brainlians !!
​\rm Numerical
1.)\rm A \: container \: contains\:5000\:g\:water\:at \:the\:height \:of\:60 \:m\:above\:ground. Then\:calculate \:the \:potential \:energy
 \rm \: 2.)A \:  electric \:  oven \:  power \:  10 \:  KW  \: is  \: used  \: for \:  3 \:  hours . Find \:  the \:  energy \:  supplied \:  by \:  the \:  heater.
  \rm3.)A  \: motor  \: is  \: used \:  to \:  lift \:  5  \: litres  \: of \:  water \:  from \:  a \:  well  \: 100 \:  m  \: deep \:  in \:  30  \: seconds \:  ( g = 10 \:  m/s^{2} ). Find \:  the \:  power  \: of  \: the \:  motor .
Best of luck my brainlians !


Answers

Answered by Anonymous
14

Answer:

1]

Given :-

Mass = 5000 g

Height = 60 m

Acceleration due to gravity = 9.8 m/s²

To Find :-

Potential energy

Solution :-

We know that

1000 g = 1 kg

5000 g = 5000/1000 = 5 kg

PE = mgh

PE = (5)(9.8)(60)

PE = 300 × 9.8

PE = 300 × 98/10

PE = 30 × 98

PE = 2940 J

2]

Given :-

Power = 10 kW

Time = 3 hours

To Find :-

Energy'

Solution :-

E = PT

E = energy

P = Power

T = Time

E = 10 × 1000 × 3 × 60 × 60

E = 10,000 × 10800

E = 108,000,000 J

E =  1.08 × 10⁸ J

3]

Given :-

Mass = 5 kg

Height = 100 m

Time = 30 seconds

G = 10 m/s²

To Find :-

Power

Solution :-

We know that

Power = Potential Energy/Time

Power = 5 × 100 × 10/30

Power = 5 × 10 × 10/3

Power = 500/3

Power = 166.66 W

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Glorious31: Great !
Answered by Ladylaurel
16

1) Question

A container contains 5000g water at the height of 60m above ground. Then calculate the potential energy.

Answer :-

The potential energy of the container is 2940J.

Step-by-step explanation:

To Find :-

  • The potential energy.

Solution

Given that,

  • Mass of the container = 5000g
  • Height of the container = 60m

Converting, 5000g to kg,

5000g

5000/1000

5kg.

We know,

Potential energy = mgh,

Where,

  • m = Mass
  • g = acceleration due to gravity and it's value is 9.8 m s -²
  • h = Height

Therefore,

mgh

m × g × h

5kg × 9.8 m s-² × 60m

2940J

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2) Question

A electric oven power 10 KW is used for 3 hours find the energy supplied by the heater.

Answer :-

The energy supplied by the heater is 1.08 × 10⁸J.

Step-by-step explanation:

To Find :-

  • The energy supplied by the heater.

Solution

Given that,

  • Power of the oven = 10 kW
  • The electric oven is used for [Time] = 3 hours

Converting, 10 kW to W and 3 hours to seconds,

→ 10 kW → W

10 × 1000

10000W

→ 3 hours → secs

3 × 60 × 60

10800 secs

We know,

E = P × t,

Where,

  • E = Energy
  • P = Power
  • t = Time.

Therefore,

P × t

10000 × 10800

108000000 or 1.08 × 10⁸ J

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3) Question

A motor is used to lift 5 litres of water from a well 100m deep in 30 seconds (g = 10 m/s²). Find the power of the motor.

Answer :-

The power of the motor is 166.66W.

Step-by-step explanation:

To Find :-

  • The power of the motor.

Solution

Given that,

  • m = 5 litres
  • g = 10 m/s-²
  • h = 100m

So, Workdone by the motor is :-

Workdone = P.E. [mgh]

mgh

5*10*100

5000J = Work done.

Now, power :-

We know,

P = W/t

Where,

  • P = Power
  • W = Workdone
  • t = Time

Therefore,

W/t

5000/30

500/3

166.66W

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Mysterioushine: Awesome! :)
Glorious31: Fantastic !
Ladylaurel: Thankyou!
ItzArchimedes: Amazing !
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Ekaro: Great!!
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