Question

Hello Brainliasm !

▶️Solve the Problem:-

▶️ Prove : A^0= 1

[Solution needed with well explanation ]



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Answer 1

Answer:

A^0= A^(1-1)

= A¹ × A^-1

= A¹/A¹

= A/A

= 1

Answer 2

$\Large{\mathfrak{\underline{\underline{Solution :-}}}}$

We know that any non - zero number divided by itself equals 1. So I can write the following.

$\sf \dfrac{2}{2} = 1$

This is same as writing :

$\sf \dfrac{2 {}^{1} }{2 {}^{1} } = 1$

Now, From Exponent and Power rule, We can utilize that

$\sf 2 {}^{1 - 1} = 1$

Of course, this is equivalent to:

$\sf 2 {}^{0} = 1$

We can use the same process as in this example, along with the generalized rule above, to show that any non-zero real number raised to the zero power must result in 1.

So, it is Proved.

$\sf A^{0} = 1$