Question

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Answer 1

Solution :-

Let ,

• Cone be ‘x’
• Cream of white color be ‘y’
• Cream of pink color be ‘z’

Given information ,

• Cone × Cone × Cone = 27

…eq(1)

• [ Cream(white) + cone ] + [ Cream(white) + cone ] = 10

…eq(2)

• [ Cream(white) + Cream(white) ] + [ Cone + Cream(pink) + Cone ] = 11

…eq(3)

• [ Cream(white) + cone ] + [ Cone ] + [ Cream(pink) + Cream(pink) + Cream(white) + cone ] = 15

Taking Equation ( 1 )

→ x × x × x = 27

→ x³ = 27

→ x = ³√27

→ x = 3 = Cone

Taking Equation ( 2 )

→ [ y + x ] + [ x + y ] = 10

→ 2x + 2y = 10

→ 2(3) + 2y = 10

→ 6 + 2y = 10

→ 2y = 10 - 6

→ 2y = 4

→ y = 4 ÷ 2

→ y = 2 = Cream ( White )

Taking Equation ( 3 )

→ [ x + y + y ] + [ x + z ] = 11

→ [ 3 + 2 + 2 ] + [ 3 + z ] = 11

→ [ 3 + 4 ] + 3 + z = 11

→ 7 + 3 + z = 11

→ 10 + z = 11

→ z = 11 - 10

→ z = 1 = Cream ( pink )

Hence ,

• Cone = 3
• Cream ( white ) = 2
• Cream ( pink ) = 1

Answer 2

Answer:

Cone=3

White cream = 2

Pink cream = 1

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Step-by-step explanation: